4(x^2+3y^2)+y(x^2+5y)=

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Solution for 4(x^2+3y^2)+y(x^2+5y)= equation:


Simplifying
4(x2 + 3y2) + y(x2 + 5y) = 0
(x2 * 4 + 3y2 * 4) + y(x2 + 5y) = 0
(4x2 + 12y2) + y(x2 + 5y) = 0
4x2 + 12y2 + (x2 * y + 5y * y) = 0
4x2 + 12y2 + (x2y + 5y2) = 0

Reorder the terms:
4x2 + x2y + 12y2 + 5y2 = 0

Combine like terms: 12y2 + 5y2 = 17y2
4x2 + x2y + 17y2 = 0

Solving
4x2 + x2y + 17y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-17y2' to each side of the equation.
4x2 + x2y + 17y2 + -17y2 = 0 + -17y2

Combine like terms: 17y2 + -17y2 = 0
4x2 + x2y + 0 = 0 + -17y2
4x2 + x2y = 0 + -17y2
Remove the zero:
4x2 + x2y = -17y2

Combine like terms: -17y2 + 17y2 = 0
4x2 + x2y + 17y2 = 0

The solution to this equation could not be determined.

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